If a transformer has 10 times more turns on the secondary side than the primary side, how will it affect the voltage?

When a transformer has a higher number of turns on the secondary side compared to the primary side, it acts as a step-up transformer. The relationship between the number of turns in the coils of a transformer and the voltages across those coils is defined by the transformer equation, which states that the ratio of the primary voltage (input) to the secondary voltage (output) is equal to the ratio of the number of turns on the primary coil to the number of turns on the secondary coil.

In this case, if there are 10 times more turns in the secondary coil than in the primary coil, the transformer will increase the voltage by a factor of 10. This means that if the primary voltage is V_p, the secondary voltage V_s can be calculated using the equation:

V_s / V_p = N_s / N_p

Where N_s is the number of turns on the secondary side and N_p is the number of turns on the primary side. Given N_s = 10 * N_p, we have:

V_s = V_p * (N_s / N_p) = V_p * 10

Therefore, the voltage on the secondary side increases by a factor of 10, confirming the accuracy of the provided answer. This