In a transformer with 25,000 primary turns and 5,000 secondary turns, what voltage is produced when 220 volts are applied?

In a transformer, the voltage across the primary and secondary coils relates to the number of turns in those coils. This relationship is defined by the formula:

[

\frac{V_s}{V_p} = \frac{N_s}{N_p}

]

where (V_s) is the secondary voltage, (V_p) is the primary voltage, (N_s) is the number of turns in the secondary coil, and (N_p) is the number of turns in the primary coil.

In this scenario, you have 25,000 primary turns and 5,000 secondary turns, with a primary voltage of 220 volts. Plugging these values into the formula gives:

[

\frac{V_s}{220} = \frac{5,000}{25,000}

]

Calculating the right side of the equation:

[

\frac{5,000}{25,000} = \frac{1}{5}

]

This tells us that the secondary voltage is one-fifth of the primary voltage. Therefore, you can multiply the primary voltage by ( \frac{1}{5} ):

[

V_s = 220 \times \frac{1}{5}